[Boost-users] boost::function as drop-in replacment for ordinary function pointers?

4 Feb 2005


      Hi,
is it possible to use boost::function as drop-in replacment for ordinary
function pointers - or are there some other solutions?
I can't get the code below to work.
thx and best regards,
Oliver

typedef void (*FunctionPointer) ( int);

void my_fun( int i)
{ std::cout << i << std::endl; }

class MyFun
{
public:
 void operator()( int i) 
 { std::cout << i << std::endl; }
};

class Test
{
public:
 void f( FunctionPointer fp)
 { fp( 1); }
};

void main()
{
 Test tst;
 MyFun mf;
 boost::function< void(int) >	f;
 f = boost::ref( mf);

// tst.f( my_fun); // works
   tst.f( f);	// ??? - doesn't compile
}

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[Boost-users] boost::function as drop-in replacment for ordinary function pointers?

Oliver Kowalke