Re: [Boost-users] Question about enable_if / disable_if

Hi! Why do you need an enable_if if you exactly know the type T? In that case you can use the temmplate specialization. template<> void f(const std::string&, bool) {...} template<> void f(const std::string&, foo) {...} template<typename T> void f(const std::string&, typename enable_if::type t) {...} On Sat, May 23, 2009 at 7:19 AM, Zachary Turner wrote:

Suppose I have a template function

template<typename T> void f(const std::string&, T);

which I want there to be a couple of different variants of.

Version 1 - Enabled if and only if boost::is_same Version 2 - Enabled if and only if boost::is_same (foo is a class) Version 3 - Enabled if and only if boost::is_enum<T> Version 4 - Otherwise

Is there an easy way to express this? It seems I run into a bunch of overload ambiguity problems. I'm sure I can get around this by adding to every version the negation of all the other conditions, but this seems unnecessarily complicated.

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