Re: [Boost-users] compiling only regex library

I.B. wrote:

...

Hi ,

i want to use boost regex++ for my project but dont want to compile all boost libraries for now, so i compiled using option: --with-regex

got no errors, and result library: boost_regex-gcc-1_33_1.a

copied all boost_<version>/boost headers to $HOME/include

directory is like this: $HOME/include/boost/regex.hpp

have a simple test.cpp file that uses:

boost::regex_search(...)

i compiled like this: g++ -o trun test.cpp -I/home/ig3/include -L/home/ig3/lib -lboost_regex-gcc-1_33_1

got following error:

test.cpp: In function `int main(int, char**)': test.cpp:26: no matching function for call to `regex_search( __gnu_cxx::__normal_iterator >&, __gnu_cxx::__normal_iterator >, boost::cmatch&, boost::regex&)'

i wonder why is that. Thought iterator is a template that shouldnt be compiled. Headers should be enough.

You've mixed your iterators up: you are passing std::string::iterator's to the function, but using boost::cmatch to accept the result (cmatch expects a const char* and *not* a string::iterator). Use boost::smatch to accept the result instead. Note: with some std lib's, std::string::iterator happens to be the type const char* and your code would compile. You can not rely on this in general though. HTH, John.