Re: [Boost-users] date_time formatting compilation error

On Sun, 14 Mar 2004 12:27:55 -0000, Keith MacDonald wrote

I'm trying to convert a gregorian::date to a string, as shown in the following code:

// Build: cl /EHsc /I \CVS\boost dt.cpp #include <iostream> #include int main() { boost::gregorian::date today(2004, boost::gregorian::Mar, 14);

std::cout << today << std::endl; return 0; }

This definately should work. What happens if you do std::cout << to_simple_string(today) << std::endl; or std::wcout << to_simple_wstring(today) << std::endl;

When I compile it with Visual C++ 7.1, using Boost from CVS head,

Are you positive about this? Changes to support wide streaming went in a couple weeks back. Seems like maybe you don't have all of that change.

I get the following error:

\CVS\boost\boost\lexical_cast.hpp(150) : error C2679: binary '>>' : no operator found which takes a right-hand operand of type 'boost::date_time::date_formatter ::string_type' (or there is no acceptable conversion) with [ date_type=boost::gregorian::date, format_type=boost::date_time::simple_format, charT=wchar_t ]

The same thing happens when using to_simple_string and to_simple_string_type<char>, rather than operator<<. I actually want the result as a basic_string, but all variations produce this same error. What am I doing wrong?

I really don't know. Can you try running the regression tests in your environment? In particular I'm interested in libs/date_time/test/gregorian/testgreg_wstream.cpp Anyway, judging from the regression tests this should be working for you... Jeff