Re: [Boost-users] fusion transform_view

Zitat von Hicham Mouline :

result_of::transform metafunction, the result type I get, printed out by typeid(...).name() gives

transform_view< Seq, UnaryFct, void_ >

is there a way to print out the actual resulting type, forcing the view to "evaluate" ?

http://www.boost.org/doc/libs/1_40_0/libs/fusion/doc/html/fusion/container/c...