Re: Re: Re: Re: Re: Re: boost.function with CW 8.2 on W2k

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CW now gives me the same error in operator safe_bool() ...<<<

I'm curious... Do you get an error when you put boost/shared_ptr.hpp in a precompiled header?

No, I had no problems with Boost in precompiled headers so far except with Boost.Function.

I'm using shared_ptr, BOOST_STATIC_ASSERT, lexical_cast, Boost.Threads, pool allocator, iterator adapters, any, ...<

shared_ptr reuses shared_ptr::get as the nonnull value, without a dummy nested class:

// implicit conversion to "bool"

typedef T * (this_type::*unspecified_bool_type)() const;

operator unspecified_bool_type() const // never throws { return px == 0? 0: &this_type::get; }

Perhaps something along these lines will work for boost::function.

OK, I think the problem is that function_base is not a template. This should fix it: diff -r1.33 function_base.hpp 268c268,269 < class function_base ---

template <typename do_not_use = int> class function_base_impl 271c272 < function_base() : manager(0), functor(static_cast(0)) {}

function_base_impl() : manager(0), functor(static_cast(0)) {}

287,291c288 < struct dummy { < void nonnull() {}; < }; < < typedef void (dummy::*safe_bool)(); ---

typedef bool (function_base_impl<>::*safe_bool)() const;

295c292 < { return (this->empty())? 0 : &dummy::nonnull; } ---

{ return (this->empty())? 0 : &function_base_impl<>::empty; }

297,298c294,295 < safe_bool operator!() const < { return (this->empty())? &dummy::nonnull : 0; } ---

bool operator!() const { return this->empty(); }

300a298,299

typedef function_base_impl<> function_base;

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