thanks now everything begins to be more understandable Inviato da iPad
Il giorno 21 lug 2021, alle ore 23:40, John Maddock via Boost-users
ha scritto: On 21/07/2021 19:07, Stefano Gragnani via Boost-users wrote:
further clarification if possible:
why the 2 lines that don't compile:
// float128 e1 = exp(1.Q); // Note argument to exp is type float128. // std::cout << e1 << std::endl; // 2.71828182845904523536028747135266231
if i put them in the following code compile regularly?
You're mixing up 2 different things:
* If you want to use __float128 "as if" it were no different to float/double etc, then include boost/math/cstdfloat.hpp
* If you want a 128-bit floating point type which hides the underlying implementation then use boost/multiprecision/float128.hpp.
Note that these are completely different approaches to the same problem, and are completely different types.
Also note that strictly speaking, boost/math/cstdfloat.hpp is NOT C++ conformant, as it adds function overloads directly to namespace std.
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