[Boost-users] Re: Guide to using serialization macro BOOST_CLASS_EXPORT

On Friday, January 7, 2005 at 10:58:13 (-0800) Robert Ramey writes:

... The whole concept behind BOOST_CLASS_EXPORT has been problematic for me for a couple of reasons. As a result, the confusion you cite is a real one.

I settled on the following that a friend suggested, which seems to work. In my serialization/util.h file, I have the following: template <class T> void save(const T* t, const std::string& filename) { ... } template <class T> T* load(const std::string& filename) { ... } at the bottom of this file, I have the following: namespace dummy { struct bogus { static int bogus_method(); }; } // force linking with util.cc static int bogus_variable = dummy::bogus::bogus_method(); in serialization/util.cc, I have: #include // expensive include which we wish to relegate to one one source file. #include // the trigger method that forces others to link with this module int dummy::bogus::bogus_method() { return 0;} The AllDerived.h file has includes for all my headers and all the BOOST_CLASS_EXPORT macros. In my application code, I do this: #include #include and it all works flawlessly. I am spared from including the headers for my derived classes, and the accompanying export macros. The save and load routines work as expected. Bill