Re: [Boost-users] Boost Lambda Newbie question

30 Nov 2006


      I managed to solve the problem, as shown in the code below. I had
mixed up the Boost.Bind and Boost.Lambda , and totally confused
myself.

Thanks, Haroon

struct some_functor
{
private:
    int x_;
public:
    some_functor& foo(int x)
    {
        std::cout<boost::format("%x-x=%d\n")%this%x_;
        return *this;
    }
};

void test16()
{
    PRINT_FUNCTION_NAME;
    using namespace boost::lambda;
    bind(&some_functor::bar, var(bind(&some_functor::foo,
var(some_functor()), _1) ) )(boost::cref(1));
    int a[] = {1, 2, 3, 4, 5, 6, 7, 8};
    std::vector<int> v(a, a+sizeof(a)/sizeof(int));

    std::for_each
        ( v.begin(), v.end()
        , bind(&some_functor::bar, var(bind(&some_functor::foo,
var(some_functor()), _1) ) ) );
}


On 11/29/06, Jaakko Järvi  wrote:
...
Can you post a full example (with main, includes and all)?
Jaakko
On Nov 27, 2006, at 9:41 PM, Haroon Khan wrote:
...
Hi,
How can we use the Boost::lambda::bind function to behave the same as
the following
class some_class{
  public:
      some_class& foo(int x){....}
      void bar() {...}
}
some_class a_object;
a_object.foo(x).bar(), where the call to some_class::foo returns a
reference to the object.
I could use Boost.Bind library to accomplish the above as follows
boost::bind(&some_class::bar, boost::bind(&some_class::foo,
some_functor(), _1))
and I need to do this using boost.lambda.
Thanks, Haroon
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