Use std::find_if, and pass it a predicate function or
function object. That is the standard way that you
override the equality function if it doesn't do what
you want.
http://www.sgi.com/tech/stl/find_if.html
This function object should work nicely:
// warning unchecked code
template<class T>
struct DerefCompare
{
bool operator()(boost::shared_ptr<T> t) const
{
return ((*t)==val);
}
DerefCompare(T inVal):val(inVal){}
T val;
};
template <class T>
DerefCompare<T> make_deref(T t)
{
return DerefCompare<T>(t);
}
Then to use it, use syntax like:
std::find_if(vec.begin(),vec.end(),make_deref(5));
Johan
--- sashan
Hi
Because the operator== function compares pointers and not what they're pointing to this is what I've had to do to get it to find an integer. Basically I had to wrap the basic int type within another class called Int, as show below.
class Int { private: shared_ptr<int> p;
public: Int(int i) {p.reset(new int); *p = i;} bool operator==(const Int& r) {return *p.get() == *r.p.get();} ~Int() {}; };
void main() { vector < Int > vec; vec.push_back(Int(1)); vec.push_back(Int(2)); vec.push_back(Int(3)); Int p(4); if (find(vec.begin(), vec.end(), p) == vec.end()) { cout << "Couldn't find it"; } }
Is there a better way that doesn't involve 1) having to write a wrapper class around a basic type (or any type) and 2) doesn't involve changing the shared_ptr::operator==.
[Non-text portions of this message have been removed]
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