Re: [Boost-users] transform_iterator and c++11 lambda expression

I use this wrapper:     #define RETURNS(...) -> decltype(__VA_ARGS__) { return (__VA_ARGS__); }     template<class Fun>     struct function_object     {         boost::optional<Fun> f;         function_object()         {}         function_object(Fun f): f(f)         {}         function_object(const function_object & rhs) : f(rhs.f)         {}         // Assignment operator is just a copy construction, which does not provide         // the strong exception guarantee.         function_object& operator=(const function_object& rhs)         {             if (this != &rhs)             {                 this->~function_object();                 new (this) function_object(rhs);             }             return *this;         }         template<class F>         struct result         {};         template         struct result         {             typedef decltype(std::declval<Fun>()(std::declval<T>())) type;         };         template<class T>         auto operator()(T && x) const RETURNS((*f)(std::forward<T>(x)))         template<class T>         auto operator()(T && x) RETURNS((*f)(std::forward<T>(x)))     };     template<class F>     function_object<F> make_function_object(F f)     {         return function_object<F>(f);     } Then you can create the transform iterator like this:     boost::make_transform_iterator(my_itertor, make_function_object([](int& i) { return i + 1; })); ----- Original Message -----

From: MM To: Boost-users@lists.boost.org Cc: Sent: Friday, September 21, 2012 6:37 PM Subject: [Boost-users] transform_iterator and c++11 lambda expression

hello it would be great to be pass

transform_iterator( my_iterator, []( reference ) {  return /// something } );

directly to STL algorithms.

Currently, one needs to define separately the unarfy function as far as i could see

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