Re: [Boost-users] [units] meta_multiply units?

Hello,

I cannot seem to figure out how to make a composite unit out of two existing units from the same system. For example, say I have a functor F which takes an argument of type

F::arg_type = quantity<time>

and returns a value of type

F::ret_type = quantity<velocity>

Now I want to write an integration function, which should return the correct type, something like

template<class F> F::ret_type*F::arg_type // only conceptually integrate(F& f, typename F::arg_type a, typename F::arg_type b);

so instantiating this with the above functor should produce a return type quantity. How can I combine F::arg_type and F::ret_type to produce the correct return type for the function template?

#include #include using namespace boost::units; // functor for velocity as a function of time struct F { typedef quantitysi::time arg_type; typedef quantitysi::velocity ret_type; // constant velocity ret_type operator()(arg_type t) const { return 1.0*si::meters/ si::second; } }; template<class F> typename multiply_typeof_helper::type integrate(F& f,typename F::arg_type a,typename F::arg_type b) { // put actual integration algorithm here... return F(b)*(b-a); } int main(void) { return 0; } There are corresponding xxx_typeof_helper functions for add, subtract, divide, pow, and root... Of course, if you're using a compiler that fully supports typeof, these shenanigans shouldn't be necessary at all. Matthias