Re: [Boost-users] Using lambda for sort

From my guess, reason is that second is a member value of a complex class. Naturally you need the address of target member function. Lambda by itself is not a particular type. It doesn't have any members function or data. The only thing it knows its value semantics.

On 8/9/07, Olaf van der Spek wrote:

On 8/9/07, Peter Dimov wrote:

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Olaf van der Spek wrote:

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sort(countries1.begin(), countries1.end(), _1->second > _2->second);

sort( countries1.begin(), countries1.end(),

bind( &countries_t::value_type::second, *_1 ) > bind( &countries_t::value_type::second, *_2 )

Thanks, that did the trick. I didn't know you could use bind like this too. But why does the simpler syntax not work? _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users