Re: [Boost-users] [lambda] Variable assignment from lambda expression

On 9/26/05, jarvi wrote:

the var function makes a lambda functor out of a variable, so you can write the expression as:

var(n) = _1

Thanks, I should have seen that one in the manual. Posting at the end of a work day is obviously not a good idea :-) I've got another lambda related question though. My example was a useless simplification, what I'm really trying to do is to read data from an STL vector into a legacy matrix class which doesn't have an iterator. for_each( raster.begin(), raster.end(), ( var( out2( h - 1 - c / w, c % w ) ) = _1, ++var( c ) ) ); -- Alex Borghgraef