Re: [Boost-Users] How to pass result of boost::bind to arg of template function ?

On Thursday 31 October 2002 01:22 pm, hugo duncan wrote:

Is this possible? if so what signature should the function have ? //! this works fine passing a boost::function object template <class ReturnType> void add(const boost::function1& arg) { boost::function1 fn_obj=arg; }

Generally speaking, it's not useful to have any of the template arguments to a Boost.Function object deduced, because it won't work the way you want it to.

//! this should work when passed the result of a boost::bind template <class ReturnType> void add(?what goes here? & arg) { function1 fn_obj(arg); } };

You could take the function object as a template paramter and extract its result_type: template<typename F> void add(F arg) { typedef typename F::result_type ReturnType; function1 fn_obj(arg); } Doug