Re: shared_ptr - implicit conversion to bool

"wasekvesely " writes:

Hi,

I've found this in "shared_ptr.hpp":

// implicit conversion to "bool" typedef T * (this_type::*unspecified_bool_type)() const;

operator unspecified_bool_type() const // never throws { return px == 0? 0: &this_type::get; }

Why this is better than:

operator bool() const { return px != 0; }

What more can I do with somethin like this?

It's not that you can do more; quite the opposite. int f(long); int x = f(shared_ptr<int>()); // error With operator bool(), that (and many other abuses) would compile. -- David Abrahams dave@boost-consulting.com * http://www.boost-consulting.com Boost support, enhancements, training, and commercial distribution