13 Sep
2012
13 Sep
'12
6:07 p.m.
On 9/12/2012 11:07 PM, Steven Watanabe wrote:
AMDG
On 09/12/2012 12:14 PM, Bill Buklis wrote:
How does one use a reference in a lambda expression? The documentation says that "var" does, but it clearly doesn't.
var does work. The argument to operator<< is passed by reference correctly. The error is that the return type is deduced as sample instead of sample&. Try wrapping the expression in bll::ret or look up how to specify the return type in the docs. I don't remember off the top of my head what you need to specialize.
Thanks. bll::ret did the trick. I knew I had to be missing something. It didn't occur to me that it was trying to copy the object *after* the expression. -- Bill