[Boost-users] Re: write_graphviz: write out edges when vertex data is a boost::shared_ptr?

I believe you need to use boost::make_label_writer. Here is how I use it to place information from an external property map: ofstream os("workFlow.dot"); write_graphviz(os,workFlowGraph_,make_label_writer(workFlowVertexLabeler(workFlowGraph_))); Where workFlowVertexLabeler is: struct workFlowVertexLabeler { workFlowVertexLabeler(WorkFlowGraph& workFlowGraph) : workFlowGraph_(workFlowGraph) {} std::string operator[](const WorkFlowVertex& v) const { return workFlowGraph_.getWorkFlowData()[v].getLabel(); } private: WorkFlowGraph& workFlowGraph_; Stephen torri wrote:

How does one write out the proper edge node names when the vertex data is a boost::shared_ptr? My graph is defined as:

typedef property< vertex_index_t, uint32_t, property< vertex_name_t, boost::shared_ptr<Component> > > VertexProperty;

typedef adjacency_list // VertexProperties Graph_Type;

The call in graphviz.hpp at line 269 has me confused. I understand that the node ids are printed out by looking for the value stored in the vertex_index_t property, graphviz.hpp at line 263. So if the value stored at the vertex_index_t property was the value '3' the node's name would be '3'. The edges are what have me confused. I would expect that the source id and the target it would be the value of the vertex_index_t property. So if there are two nodes the dot file would be:

0[label="A"]; 1[label="B"]; 0 -> 1;

Yet with a boost::shared_ptr stored in a vertex_name_t property I get:

0[label="A"]; 1[label="B"]; 0x807a108->0x807a128;

Well anything starting with a '0x' is ambigiuos to the dot parser. It breaks the 0x807a108 into two names.

I need to use a boost::shared_ptr for my data. I believe I have not used the right boost::property type. Is that right?

What I expect to see as output for the dot file is:

0[label="A"]; 1[label="B"]; 0->1;

Stephen