Re: [Boost-users] [bind / lambda] binding a factory funtion instead ofan value

Bertolt Mildner wrote:

Lets say i need a functor of type

typedef boost::function1 Functor;

and i have a function

Ret Foo(Arg1 a, Arg2 b);

Creating a Functor object is easy if i have a Arg2 object

Arg2 arg2;

Functor f(boost::bind<Ret>(&Foo, _1, arg2);

But what if i want to create the Arg2 object in the functor when it is used?

Like i have a function

Arg2 CreateArg2();

and i don't want

Functor f(boost::bind<Ret>(&Foo, _1, CreateArg2());

but something like

Functor f(boost::bind<Ret>(&Foo, _1, &CreateArg2);

so that f(arg1) = Foo(arg1, CreateArg2());

bind( Foo, _1, bind( CreateArg2 ) ).