Re: [Boost-users] [bind / lambda] binding a factory funtion insteadofan value

"Peter Dimov" schrieb im Newsbeitrag news:000c01c57782$32d4ae20$6401a8c0@pdimov2...

...

but something like

Functor f(boost::bind<Ret>(&Foo, _1, &CreateArg2);

so that f(arg1) = Foo(arg1, CreateArg2());

bind( Foo, _1, bind( CreateArg2 ) ).

Ha, it is realy obvious! Now i'm also able to find it in the docu :)) Thanks a lot! Bertolt