I want to expand the File_Base virtual interface here to allow me to
pass the 'file_data' from the File class without have two sets of code:
if (size == 32)
32 bite code
else
64 bite code
How do I expand the File_base interface? Is there a way to grab the type
of a variable passed into a function and reuse it at run time?
So that one time doSomething would have the following if the 'file_data'
variable was passed in the File_Base interface:
void doSomething (boost::shared_ptr const& f)
{
File<32> a = f->get_File();
// do 32 bit code
}
While another time the function code be:
void doSomething (boost::shared_ptr const& f)
{
File<64> a = f->get_File();
// do 64 bit code
}
I would like to be generic so I don't have to repeat the same code.
Stephen
--------- SAMPLE PROGRAM --------
#include <iostream>
#include
/*! \brief Type Mapper type */
template <int size> struct Type_Mapper;
/*! \brief 32-bit Type Mapper */
template <>
struct Type_Mapper<32> {
/*! \brief 32-bit type */
typedef uint32_t arch_t;
};
/*! \brief 64-bit Type Mapper */
template <>
struct Type_Mapper<64> {
/*! \brief 64-bit type */
typedef uint64_t arch_t;
};
class File_Base {
public:
virtual uint32_t const get_Size() = 0;
};
template
class File : public File_Base
{
public:
virtual uint32_t const get_Size()
{
return size;
}
typename Type_Mapper<size>::arch_t file_data;
};
void doSomething (boost::shared_ptr const& f)
{
// Needs to access the variable 'file_data' in File<size>
// Problem: How to expand File_Base interface so that
// the variable 'file_data' can be returned without have
// code like:
if (f->get_Size() == 32)
{
// do 32 bit code
}
else
{
// do 64 bit code
}
}
void create (void)
{
boost::shared_ptr f (new File<32>());
doSomething (f);
}
int main (int, char*) {
create ();
return 0;
}
Stephen torri