Hello, I have tried to compile the following code with the Microsoft Visual C++ 7.1 compiler. #include int main(int argc, char** argv) { using namespace std; using namespace boost; wstring wstrFoo = boost::lexical_cast<wstring>( 200 ); return 0; } If I compile this example with native wchar_t support (/Zc:wchar_t) everything works fine. Otherwise, if I compile the example without native wchar_t compiler support, I encounter the following compiler error: d:\Temp\Boost\boost\lexical_cast.hpp(150) : error C2679: binary '>>' : no operator found which takes a right-hand operand of type 'std::wstring' (or there is no acceptable conversion) d:\Temp\Boost\boost\lexical_cast.hpp(189) : see reference to function template instantiation 'bool boost::detail::lexical_stream::operator >><Target>(InputStreamable &)' being compiled with [ Target=std::wstring, Source=int, InputStreamable=std::wstring ] d:\Temp\BoostConsole\BoostConsole.cpp(12) : see reference to function template instantiation 'Target boost::lexical_caststd::wstring,int(Source)' being compiled with [ Target=std::wstring, Source=int ] As I can see in the header file "lexical_cast.hpp" the macro BOOST_NO_INTRINSIC_WCHAR_T is defined, if the compiler option /Zc:wchar_t is not specified. This causes the macro DISABLE_WIDE_CHAR_SUPPORT to be defined as well and thus the lexical_stream::operator(std::wstring) will not be compiled. Do anyone know a workaround, so that I can use lexical_cast without native wchar_t compiler support and wstring? Is it really necessary to define DISABLE_WIDE_CHAR_SUPPORT, if BOOST_NO_INTRINSIC_WCHAR_T is defined only? For testing purposes I have commented out the two #ifndef DISABLE_WIDE_CHAR_SUPPORT statement. Now, I could compile the example without native wchar_t support. But I think, that this results in side effects, which I'm not able to see. Regards, Jochen.