"Gennadiy Rozental" wrote in message news:loom.20100206T071834-814@post.gmane.org...

You can send in a patch which will make Boost.Test work with both ostream and wostream. Also you cna write an operator << (ostream&,wstring const&)

I tried to put the operator above "#include ", but the same error persists, and mine is not in the candidate operator overload list displayed in the message - only operators defined in <ostream> are listed. My operator lets me output wstrings to std::cout from test cases, but when "boost\test\test_tools.hpp" tries to do it, it does not compile. I am using boost 1.41.0 and vc9. Here is my code and the error: #include <iostream> #include <string> std::ostream & operator << (std::ostream & stream, const std::wstring & str) { return stream << "std::wstring"; } #define BOOST_TEST_MODULE const_string test #include BOOST_AUTO_TEST_CASE(Test) { std::wstring wstr; std::cout << wstr; // OK BOOST_CHECK_EQUAL(wstr, wstr); // Error } test.cpp ...\boost\test\test_tools.hpp(326) : error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'const std::wstring' (or there is no acceptable conversion) ... while trying to match the argument list '(std::ostream, const std::wstring)' ...\boost\test\test_tools.hpp(318) : while compiling class template member function 'void boost::test_tools::print_log_value<T>::operator ()(std::ostream &,const T &)' with [ T=std::wstring ]

Unfortunately I believe there only way to circumvent this it to define the operator in namespace std.

Ah, totally forgot this can be a problem. Thanks, it works now.