New subject: Boost.Function: How does the template param mechanism work?

19 Jun 2005

      My question is, given:

boost::function< int (char, long) > func(&f);

how is it possible to pass the (char,long)? (I tried to receive this in
a template as a single template param, or as three , but neither worked)

I have been studying the headers, but the indirection used (FTSE :) ) is
making it hard for me to figure this one out.

The reason I am asking I is I am trying to clean up the syntax of some
template params and I would like to use this technique.

i.e. I would like to write:
struct A {};
struct B {};
struct C {};
struct D {};
struct E {};
struct F {};

typedef MyThingdef<  	(A,B),
				(C,D),
				(E,F) > splat;

instead of

typedef MyThingdef<  	A,B,
				C,D,
				E,F > splat;

Any direction on things to research or dig into appreciated.

Thanks

Brian

Brian Braatz