From: "Peter Dimov" <pdimov@pdimov.com> Subject: Re: [Boost-users] [enable_shared_from_this] My derivation ofenable_shared_from_this wants to be templated

...

template<class X> class Y: public enable_shared_from_this< Y<X> > { public:

shared_ptr< Y<X> > f() { return shared_from_this();

In a template, you need

return this->shared_from_this();

to inform the compiler that shared_from_this will come from a base class.

...

}

perfect ... thank you.