Thanks. bind(&test_thread, s) works. How can I bind one boost::thread to another boost::thread? Here is what I want to do: void work_thread() { cout << "done" << endl; } void test_thread(boost::thread& t) { while (t.joinable()) { // do sth. this_thread::sleep(seconds(2)); } } int main() { boost::thread work_thread(work_thread); // this line does not compile boost::thread inquiry_thread(bind(&test_thread, work_thread ) ); work_thread.join(); inquiry_thread.join(); return 0; } Thanks in advance. Robert On Thu, Sep 10, 2009 at 4:24 PM, Eric MALENFANT < Eric.Malenfant@sagem-interstar.com> wrote:

Boost lzw wrote: [snip]

...

but the lambda version does not compile. Why? Thanks. -------------------------------------

...

void test_thread(std::string s) { cout << "string is" << s << endl; }

std::string s("I am a string"); boost::thread inquiry_thread(bind(test_thread, _1)(s) );

bind(test_thread, _1) creates a functor expecting one argument. Appending "(s)" right after invokes that functor, passing it s as an argument.

What you want is: bind(&test_thread, s)

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