On Tue, Jan 27, 2009 at 7:24 PM, Mario Chacon wrote:

Hello: I have this problem and I do not how to fix it, I know I cannot write template typedefs, its a limitiation of the C++ syntax, right? or I'm wrong? I saw that the best way is to wrap your typedefs in a struct, which can be templated, but I'm still stack with problems. The best way to explain it's with an example:

#include <cstdlib> #include <iostream> #include

template< typename tvalue > class CValue { public: CValue( tvalue value ) : value_(value) {};

private: tvalue value_; };

template< typename tvalue > struct Type{ typedef boost::shared_ptr< CValue< tvalue > > pValue; };

int main(int argc, char *argv[]) { Type<bool>::pValue a;

return EXIT_SUCCESS; }

How can I create a shared_ptr for the template class "CVALUE"?? Please I do not know what else I can prove... :(

Your code seems to compile fine, what's the problem? Emil Dotchevski Reverge Studios, Inc. http://www.revergestudios.com/reblog/index.php?n=ReCode

replace Type<bool>::pValue a; with typename Type<bool>::pValue a; ? B/Rgds Max Hello: I have this problem and I do not how to fix it, I know I cannot write template typedefs, its a limitiation of the C++ syntax, right? or I'm wrong? I saw that the best way is to wrap your typedefs in a struct, which can be templated, but I'm still stack with problems. The best way to explain it's with an example: #include <cstdlib> #include <iostream> #include template< typename tvalue > class CValue { public: CValue( tvalue value ) : value_(value) {}; private: tvalue value_; }; template< typename tvalue > struct Type{ typedef boost::shared_ptr< CValue< tvalue > > pValue; }; int main(int argc, char *argv[]) { Type<bool>::pValue a; return EXIT_SUCCESS; }