New subject: [Boost-Users] lambda library bug --- endl?

13 Sep 2002

      Hi there.

I have a recent CVS version of Boost installed, and am using g++ v3.2.  I
tried to compile the following program:

-----------lambda_test.cpp------------
#include <iostream>
#include <string>
#include <list>
#include <algorithm>
#include 

using namespace std;
using namespace boost::lambda;

int main() 
{
    list<int> ell;

    for (int i=0; i<100; ++i)
        ell.push_back(4*i-1);

    for_each(ell.begin(), ell.end(), cout << _1 << endl);
}
--------------------------------------

I am met by:

% g++ -I/usr/local/boost -c lambda_test.cpp
lambda_test.cpp: In function `int main()':
lambda_test.cpp:17: no match for `const
boost::lambda::lambda_functorboost::lambda::leftshift_action,
   boost::tuples::tuple >, 
   boost::tuples::null_type, boost::tuples::null_type, 
   boost::tuples::null_type, boost::tuples::null_type, 
   boost::tuples::null_type, boost::tuples::null_type, 
   boost::tuples::null_type, boost::tuples::null_type> > > << <unknown type>' 
   operator

Any suggestions?  I am aware that I can replace endl by '\n' and get a
compilable program.  I worry that this problem extends to other
manipulators...

Thanks,
Ken

lambda library bug --- endl?

Ken Yarnall

Jaakko Jarvi

Kenneth Yarnall

Jaakko Jarvi

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