Hi Yu, I happen to have finished reading lambda docs just a while ago... :-) std::cout << (_1 + _2)(boost::lambda::make_const(10), boost::lambda::make_const(10)); std::cout << std::endl; does the job. You have to be careful about passing constants as arguments, see docs for details. As for std::endl, the problem is that the resulting value (result of std::cout << _lambda_expression_) has some special type. There are some workarounds, try googling on that if this worries you. Cheers, Filip

Hi,

It seems that the lambda manual lacks of a simple working example.

I'm made up the following example. But it's not working. Could you please show me how to make it work?

Thanks, Peng

#include #include #include <iostream>

using namespace boost::lambda;

int main() { std::cout << (_1 + _2)(10, 10) << std::endl; } _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users

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