Just after the sending I have realize a typo. Instead of this: typedef find_iteratorstring::iterator string_find_iterator; use this: typedef split_iteratorstring::iterator string_find_iterator; On Fri, Dec 23, 2005 at 07:04:08PM +0100, Pavol Droba wrote:

Hi,

You might be able to do it using the string_algo find_iterator.

#include

using namespace std; using namespace boost;

...

typedef find_iteratorstring::iterator string_find_iterator; string_find_iterator It=make_find_iterator(str1, token_finder(is_space()));

for(int i=0; i

Regards, Pavol

On Fri, Dec 23, 2005 at 07:30:48PM +0200, Alex Vinokur wrote:

...

Can the boost Tokenizer package split a string into into a series of serieses of tokens (a vector of vectors of tokens)?

==================== For instance, string s = "ab cd \nxy z\n123";

vector v;

Output should be as follows: v[0][0] = "ab"; v[0][1] = "cd";

v[1][0] = "xy"; v[1][1] = "z";

v[2][0] = "123"; ====================

http://boost.org/libs/tokenizer/introduc.htm doesn't contain such a sample.

Alex Vinokur email: alex DOT vinokur AT gmail DOT com http://mathforum.org/library/view/10978.html http://sourceforge.net/users/alexvn

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On Sat, Dec 24, 2005 at 09:06:51AM +0200, Alex Vinokur wrote:

"Pavol Droba" wrote in message news:20051223180408.GP15407@lenin.felcer.sk...

...

Hi,

You might be able to do it using the string_algo find_iterator.

#include

using namespace std; using namespace boost;

...

[snip] typedef split_iteratorstring::iterator string_find_iterator; ------------------------------------------------------------------------------

...

string_find_iterator It=make_find_iterator(str1, token_finder(is_space()));

That line produces the following error message:

error: conversion from `boost::algorithm::find_iterator<__gnu_cxx::__normal_iterator > >' to non-scalar type `boost::algorithm::split_iterator<__gnu_cxx::__normal_iterator > >' requested

Sorry, I have fixed one error, but the other line was tied to it. the second line should be string_find_iterator It=make_split_iterator(str1, token_finder(is_space())); Regards, Pavol