I think I found the solution to my problem. If I add the following to my program: namespace boost { namespace detail { /** Fix for boost::result_of */ template struct result_of { typedef R type; }; /** Fix for boost::result_of */ template struct result_of { typedef R type; }; } //namespace detail } //namespace boost Then boost::result_of "learns" how to detect the result type of a member function signature with no parameters. Now the question is: why is this specialization not provided by boost? Should it be? Thanks -delfin

-----Original Message----- From: boost-users-bounces@lists.boost.org [mailto:boost-users- bounces@lists.boost.org] On Behalf Of Delfin Rojas Sent: Wednesday, April 27, 2005 2:22 PM To: boost-users@lists.boost.org Subject: [Boost-users] Function pointers, result_of<> and function_traits<>

Hello all,

I am trying to get the return type of a member function given its signature. Consider the following example from the boost result_of test:

struct X {};

int main { using namespace boost; typedef int (X::*mem_func_ptr)(float);

BOOST_STATIC_ASSERT((is_same::type, int>::value)); }

This test compiles/runs with no problems. Now, what I want is the return type of a function with signature "int (X::*)()"

I added the following to the test:

typedef int (X::*empty_mem_func_ptr)();

BOOST_STATIC_ASSERT((is_same::type, int>::value));

This does not compile. I get an error boost_1_32_0\boost\utility\result_of.hpp(43) : error C2825: 'F::template': cannot form a qualified name.

I tried to do this same thing with function_traits but it seems function traits does not support member function pointers at all.

So this is all I have. If somebody can help me I would appreciate it.

Thanks

-delfin

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