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fusion transform_view

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Hicham Mouline

12 Sep 2010 12 Sep '10

10:43 a.m.

Hello After I invoke the result_of::transform metafunction, the result type I get, printed out by typeid(...).name() gives transform_view< Seq, UnaryFct, void_ > is there a way to print out the actual resulting type, forcing the view to "evaluate" ? regards,

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Stefan Strasser

12 Sep 12 Sep

3:31 p.m.

Zitat von Hicham Mouline :

result_of::transform metafunction, the result type I get, printed out by typeid(...).name() gives

transform_view< Seq, UnaryFct, void_ >

is there a way to print out the actual resulting type, forcing the view to "evaluate" ?

http://www.boost.org/doc/libs/1_40_0/libs/fusion/doc/html/fusion/container/c...

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Hicham Mouline
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