30 Apr
2015
30 Apr
'15
6:31 p.m.
But std::deque depends on (as does some of my other code) it's type having a default constructor. I'm surprised it does not already exists.
In what situation are you finding the std::deque requires an object to be default constructible? As far as I know this is simply not true for any std containers so I'd like to know how you've happened upon this. -- chris