---------- Forwarded message ----------
From: Andrey Semashev
2015-05-23 18:33 GMT+02:00 Steven Watanabe
: AMDG
On 05/23/2015 09:44 AM, Peter Dimov wrote:
Why doesn't Typeof use decltype on VS 2013?
Probably because Typeof hasn't had a maintainer since before decltype. It doesn't appear to use decltype for any compiler.
I don't think it can. The semantics of BOOST_TYPEOF is that of: auto x = expr;
The semantics of decltype are quire different. For instance, auto and BOOST_TYPEOF and GCC's __typeof__ never deduce references -- always values. decltype on the other hand can deduce references.
As long as BOOST_TYPEOF is less precise than decltype it can be
emulated, can it not?
You're right it can. I think the following would work:
typename std::decay