Re: [boost] [operators] A modern SFINAE-based version of boost::operators?

of course I mean: Foo operator+(Foo l, Foo const& r) { return l += r; return l; } in the second version. On 13 November 2017 at 16:05, Richard Hodges wrote:

I for one would be grateful for work on this. Particularly if it also automatically manufactures move-aware versions of binary operators.

eg:

Foo&& operator+(Foo&& l, Foo const& r) { return std::move(l += r); } Foo operator+(Foo const& l, Foo const& r) { return l += r; return l; }

On 13 November 2017 at 15:20, Beman Dawes via Boost

...

wrote:

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Peter Sommerlad, committee member and C++Now presenter who often proposes additions to fill in holes in the standard library, asked me:

Are you aware of anybody who tried to provide a boost::operators style of automatically providing additional operators with a single base class that through SFINAE injects all possible operators based on the ones defined in the template parameter? This won't give you the control of the current boost::operators, but would be much easier to teach.

For example

struct Me : make_operators_for<Me>{ Me& operator+=(Me const&); // You get + bool operator<(Me const&) const; // You get all relops (<=> will make that obsolete) Me& operator++(); // you get postfix //etc. };

Today we have the facilities and compilers to make that happen.

What do you think? Who should I ask?

Anyone doing any work on operators or have any thoughts about updating boost::operators?

--Beman

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