Re: [boost] [multiprecision] General/design query about which conversions should be implicit/explicit

Does the floating point to rational multiprecision-types really don't loss information, i.e. does the following hold?

double d1 = 0.1; rational_mp r1 = d1; double d2 = double(r1); rational_mp r2 = d2; assert(r1==r2);

It does hold yes. John.