On 11 May 2017 at 08:11, Edward Diener via Boost
There is no reason to change the right-to-left order as the most significant bit is on the right.
A bitset is not a number, 'most signifcant' depends on usage and is in the eye of the beholder.
Furthermore it would be foolish to break backward compatibility on a whim.
Yes. I will probably keep the same order but just add that the longer size, the
rest being equal, will always be considered greater than the shorter size.
One could introduce a comparison-policy, the default preserving the 'current' behaviour.
The only other possibility that I can imagine, if the assert is eliminated, is to throw some exception if the sizes are not equal, which at least has the possibility of keeping the program running if the exception is caught.
An exception seems completely wrong to me, as there is a valid use case for comparing bitsets of differing lengths. Exceptions should be used for exceptional situations, i.e. not here. degski -- "*Ihre sogenannte Religion wirkt bloß wie ein Opiat reizend, betäubend, Schmerzen aus Schwäche stillend.*" - Novalis 1798