On 1/27/21 11:58 PM, Gavin Lambert via Boost wrote:
((uint32_t) -1) assumed equivalent to 0xFFFFFFFFu (which is not guaranteed)
Is it not? IIRC, by the standard C++ the above is equivalent to
`(uint32_t)((uint32_t)0u - 1)`, which must give 0xFFFFFFFF.
