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On 03/13/2016 06:01 PM, Phil Bouchard wrote:
Because you can still call the function using a root_ptr<>: int main() { root_ptr<int> p(new block<int>(10)); foo(p); }
Because you can still call the function using a root_ptr<>:
int main() { root_ptr<int> p(new block<int>(10));
foo(p); }
I meant: int main() { root_ptr<int> p(new node<int>(10)); foo(p); }
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