2015-06-22 16:59 GMT+02:00 Tobias Loew
I deliberately used this std::bind syntax since it accepts any callable (including things like pointer-to-member [functions]). I tried lambdas with my code and they just work. E.g.
auto opt_i3 = map(opt_a, [](const A& a){ return a.i;}); assert(*opt_i3 == 42);
Interesting. Is it implementable in C++03?
Furthermore without the std::decay boost::optional
will be a boost::optional . Tobias
Von: Andrzej Krzemienski [via Boost] [mailto: ml-node+s2283326n4677436h22@n4.nabble.com] Gesendet: Montag, 22. Juni 2015 16:44 An: Löw, Tobias (STEAG Energy Services GmbH) Betreff: Re: [Optional] Monadic bind
2015-06-22 16:17 GMT+02:00 Tobias Loew <[hidden email]>:
Sorry for that,
I've made in implementation with free functions which compiles on VS 2012:
#include
#include template
auto bind(const boost::optional<T>& optional, B&& binder) -> typename std::decay ::type { if(optional) { return std::bind(binder, *optional)(); } else { return boost::none; } } template
auto map(const boost::optional<T>& optional, B&& binder) -> boost::optional ::type> { if(optional) { return std::bind(binder, *optional)(); } else { return boost::none; } } void foo() { struct A { int i; }; boost::optional<A> opt_a;
auto opt_i = map(opt_a, &A::i); assert(!opt_i);
A a = {42}; opt_a = a;
auto opt_i2 = map(opt_a, &A::i); assert(*opt_i2 == 42);
}
Would you find the following an acceptable solution?
``` #include
#include #include template
auto map2(const boost::optional<T>& o, F f) -> boost::optional { if (o) return f(*o); else return boost::none; } void foo() { struct A { int i; }; boost::optional<A> opt_a;
auto opt_i = map2(opt_a, boost::bind(&A::i, _1)); assert(!opt_i);
A a = {42}; opt_a = a;
auto opt_i2 = map2(opt_a, boost::bind(&A::i, _1)); assert(opt_i2); assert(*opt_i2 == 42); }
int main() { foo(); } ```
It requires of you to type a bit more, but at the same time it is more flexible: you can type any free function on T, including a lambda.
Regards, &rzej
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